-2(-n-3)=4(n-4)

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Solution for -2(-n-3)=4(n-4) equation: 



-2(-n-3)=4(n-4)

We move all terms to the left:

-2(-n-3)-(4(n-4))=0

We add all the numbers together, and all the variables

-2(-1n-3)-(4(n-4))=0

We multiply parentheses

2n-(4(n-4))+6=0



We calculate terms in parentheses: -(4(n-4)), so:

4(n-4)

We multiply parentheses

4n-16

Back to the equation:

-(4n-16)



We get rid of parentheses

2n-4n+16+6=0

We add all the numbers together, and all the variables

-2n+22=0

We move all terms containing n to the left, all other terms to the right

-2n=-22

n=-22/-2

n=+11

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