-2(-x+5)+6(3x+1)=-3(2x-5)-4(1+4x)-8

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Solution for -2(-x+5)+6(3x+1)=-3(2x-5)-4(1+4x)-8 equation:



-2(-x+5)+6(3x+1)=-3(2x-5)-4(1+4x)-8
We move all terms to the left:
-2(-x+5)+6(3x+1)-(-3(2x-5)-4(1+4x)-8)=0
We add all the numbers together, and all the variables
-2(-1x+5)+6(3x+1)-(-3(2x-5)-4(4x+1)-8)=0
We multiply parentheses
2x+18x-(-3(2x-5)-4(4x+1)-8)-10+6=0
We calculate terms in parentheses: -(-3(2x-5)-4(4x+1)-8), so:
-3(2x-5)-4(4x+1)-8
We multiply parentheses
-6x-16x+15-4-8
We add all the numbers together, and all the variables
-22x+3
Back to the equation:
-(-22x+3)
We add all the numbers together, and all the variables
20x-(-22x+3)-4=0
We get rid of parentheses
20x+22x-3-4=0
We add all the numbers together, and all the variables
42x-7=0
We move all terms containing x to the left, all other terms to the right
42x=7
x=7/42
x=1/6

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