-2(-x+9)=2(x-9)2x-18=2x-18

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Solution for -2(-x+9)=2(x-9)2x-18=2x-18 equation:



-2(-x+9)=2(x-9)2x-18=2x-18
We move all terms to the left:
-2(-x+9)-(2(x-9)2x-18)=0
We add all the numbers together, and all the variables
-2(-1x+9)-(2(x-9)2x-18)=0
We multiply parentheses
2x-(2(x-9)2x-18)-18=0
We calculate terms in parentheses: -(2(x-9)2x-18), so:
2(x-9)2x-18
We multiply parentheses
4x^2-36x-18
Back to the equation:
-(4x^2-36x-18)
We get rid of parentheses
-4x^2+2x+36x+18-18=0
We add all the numbers together, and all the variables
-4x^2+38x=0
a = -4; b = 38; c = 0;
Δ = b2-4ac
Δ = 382-4·(-4)·0
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-38}{2*-4}=\frac{-76}{-8} =9+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+38}{2*-4}=\frac{0}{-8} =0 $

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