-2(1+3b)=30+2b

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Solution for -2(1+3b)=30+2b equation: 



-2(1+3b)=30+2b

We move all terms to the left:

-2(1+3b)-(30+2b)=0

We add all the numbers together, and all the variables

-2(3b+1)-(2b+30)=0

We multiply parentheses

-6b-(2b+30)-2=0

We get rid of parentheses

-6b-2b-30-2=0

We add all the numbers together, and all the variables

-8b-32=0

We move all terms containing b to the left, all other terms to the right

-8b=32

b=32/-8

b=-4

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