-2(1+4b)+2(-3+3b)=2

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Solution for -2(1+4b)+2(-3+3b)=2 equation: 



-2(1+4b)+2(-3+3b)=2

We move all terms to the left:

-2(1+4b)+2(-3+3b)-(2)=0

We add all the numbers together, and all the variables

-2(4b+1)+2(3b-3)-2=0

We multiply parentheses

-8b+6b-2-6-2=0

We add all the numbers together, and all the variables

-2b-10=0

We move all terms containing b to the left, all other terms to the right

-2b=10

b=10/-2

b=-5

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