-2(1+8k)-2(1+3k)=k-4-2k

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Solution for -2(1+8k)-2(1+3k)=k-4-2k equation: 



-2(1+8k)-2(1+3k)=k-4-2k

We move all terms to the left:

-2(1+8k)-2(1+3k)-(k-4-2k)=0

We add all the numbers together, and all the variables

-2(8k+1)-2(3k+1)-(-1k-4)=0

We multiply parentheses

-16k-6k-(-1k-4)-2-2=0

We get rid of parentheses

-16k-6k+1k+4-2-2=0

We add all the numbers together, and all the variables

-21k=0

k=0/-21

k=0

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