-2(1+b)=(b-8)-3

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Solution for -2(1+b)=(b-8)-3 equation:


Simplifying
-2(1 + b) = (b + -8) + -3
(1 * -2 + b * -2) = (b + -8) + -3
(-2 + -2b) = (b + -8) + -3

Reorder the terms:
-2 + -2b = (-8 + b) + -3

Remove parenthesis around (-8 + b)
-2 + -2b = -8 + b + -3

Reorder the terms:
-2 + -2b = -8 + -3 + b

Combine like terms: -8 + -3 = -11
-2 + -2b = -11 + b

Solving
-2 + -2b = -11 + b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1b' to each side of the equation.
-2 + -2b + -1b = -11 + b + -1b

Combine like terms: -2b + -1b = -3b
-2 + -3b = -11 + b + -1b

Combine like terms: b + -1b = 0
-2 + -3b = -11 + 0
-2 + -3b = -11

Add '2' to each side of the equation.
-2 + 2 + -3b = -11 + 2

Combine like terms: -2 + 2 = 0
0 + -3b = -11 + 2
-3b = -11 + 2

Combine like terms: -11 + 2 = -9
-3b = -9

Divide each side by '-3'.
b = 3

Simplifying
b = 3

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