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-2(1-2x)-(1-2x)=-x2
We move all terms to the left:
-2(1-2x)-(1-2x)-(-x2)=0
We add all the numbers together, and all the variables
-(-1x^2)-2(-2x+1)-(-2x+1)=0
We multiply parentheses
-(-1x^2)+4x-(-2x+1)-2=0
We get rid of parentheses
1x^2+4x+2x-1-2=0
We add all the numbers together, and all the variables
x^2+6x-3=0
a = 1; b = 6; c = -3;
Δ = b2-4ac
Δ = 62-4·1·(-3)
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-4\sqrt{3}}{2*1}=\frac{-6-4\sqrt{3}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+4\sqrt{3}}{2*1}=\frac{-6+4\sqrt{3}}{2} $
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