-2(1-2x)-(1-2x)=-x2

Solution for -2(1-2x)-(1-2x)=-x2 equation:

-2(1-2x)-(1-2x)=-x2

We move all terms to the left:

-2(1-2x)-(1-2x)-(-x2)=0

We add all the numbers together, and all the variables

-(-1x^2)-2(-2x+1)-(-2x+1)=0

We multiply parentheses

-(-1x^2)+4x-(-2x+1)-2=0

We get rid of parentheses

1x^2+4x+2x-1-2=0

We add all the numbers together, and all the variables

x^2+6x-3=0

a = 1; b = 6; c = -3;
Δ = b2-4ac
Δ = 62-4·1·(-3)
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-4\sqrt{3}}{2*1}=\frac{-6-4\sqrt{3}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+4\sqrt{3}}{2*1}=\frac{-6+4\sqrt{3}}{2}
$