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-2(1-5v)=-(2-4v)
We move all terms to the left:
-2(1-5v)-(-(2-4v))=0
We add all the numbers together, and all the variables
-2(-5v+1)-(-(-4v+2))=0
We multiply parentheses
10v-(-(-4v+2))-2=0
We calculate terms in parentheses: -(-(-4v+2)), so:We get rid of parentheses
-(-4v+2)
We get rid of parentheses
4v-2
Back to the equation:
-(4v-2)
10v-4v+2-2=0
We add all the numbers together, and all the variables
6v=0
v=0/6
v=0
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