-2(10+2b)=32

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Solution for -2(10+2b)=32 equation: 



-2(10+2b)=32

We move all terms to the left:

-2(10+2b)-(32)=0

We add all the numbers together, and all the variables

-2(2b+10)-32=0

We multiply parentheses

-4b-20-32=0

We add all the numbers together, and all the variables

-4b-52=0

We move all terms containing b to the left, all other terms to the right

-4b=52

b=52/-4

b=-13

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