-2(10-3b)=6(b+3)+2

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Solution for -2(10-3b)=6(b+3)+2 equation: 



-2(10-3b)=6(b+3)+2

We move all terms to the left:

-2(10-3b)-(6(b+3)+2)=0

We add all the numbers together, and all the variables

-2(-3b+10)-(6(b+3)+2)=0

We multiply parentheses

6b-(6(b+3)+2)-20=0



We calculate terms in parentheses: -(6(b+3)+2), so:

6(b+3)+2

We multiply parentheses

6b+18+2

We add all the numbers together, and all the variables

6b+20

Back to the equation:

-(6b+20)



We get rid of parentheses

6b-6b-20-20=0

We add all the numbers together, and all the variables

-40!=0

There is no solution for this equation

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