-2(10-3b)=6(b-3)-2

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Solution for -2(10-3b)=6(b-3)-2 equation: 



-2(10-3b)=6(b-3)-2

We move all terms to the left:

-2(10-3b)-(6(b-3)-2)=0

We add all the numbers together, and all the variables

-2(-3b+10)-(6(b-3)-2)=0

We multiply parentheses

6b-(6(b-3)-2)-20=0



We calculate terms in parentheses: -(6(b-3)-2), so:

6(b-3)-2

We multiply parentheses

6b-18-2

We add all the numbers together, and all the variables

6b-20

Back to the equation:

-(6b-20)



We get rid of parentheses

6b-6b+20-20=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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