-2(10x-15)=1/2(-40x+60)

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Solution for -2(10x-15)=1/2(-40x+60) equation: 



-2(10x-15)=1/2(-40x+60)

We move all terms to the left:

-2(10x-15)-(1/2(-40x+60))=0



Domain of the equation: 2(-40x+60))!=0

x∈R



We multiply parentheses

-20x-(1/2(-40x+60))+30=0

We multiply all the terms by the denominator


-20x*2(-40x+60))-(1+30*2(-40x+60))=0

Wy multiply elements

-40x^2(-+60x(-=0

We use the square of the difference formula

-40x^2(-60x(-=0

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