-2(11b-3)b=5

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Solution for -2(11b-3)b=5 equation: 



-2(11b-3)b=5

We move all terms to the left:

-2(11b-3)b-(5)=0

We multiply parentheses

-22b^2+6b-5=0

a = -22; b = 6; c = -5;
Δ = b2-4ac
Δ = 62-4·(-22)·(-5)
Δ = -404
Delta is less than zero, so there is no solution for the equation

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