-2(2+2n)=4(2+2n)

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Solution for -2(2+2n)=4(2+2n) equation: 



-2(2+2n)=4(2+2n)

We move all terms to the left:

-2(2+2n)-(4(2+2n))=0

We add all the numbers together, and all the variables

-2(2n+2)-(4(2n+2))=0

We multiply parentheses

-4n-(4(2n+2))-4=0



We calculate terms in parentheses: -(4(2n+2)), so:

4(2n+2)

We multiply parentheses

8n+8

Back to the equation:

-(8n+8)



We get rid of parentheses

-4n-8n-8-4=0

We add all the numbers together, and all the variables

-12n-12=0

We move all terms containing n to the left, all other terms to the right

-12n=12

n=12/-12

n=-1

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