-2(2+3)-2=-2-4(z+2)

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Solution for -2(2+3)-2=-2-4(z+2) equation: 



-2(2+3)-2=-2-4(z+2)

We move all terms to the left:

-2(2+3)-2-(-2-4(z+2))=0

We add all the numbers together, and all the variables

-(-2-4(z+2))-2-25=0

We add all the numbers together, and all the variables

-(-2-4(z+2))-27=0



We calculate terms in parentheses: -(-2-4(z+2)), so:

-2-4(z+2)

determiningTheFunctionDomain
-4(z+2)-2

We multiply parentheses

-4z-8-2

We add all the numbers together, and all the variables

-4z-10

Back to the equation:

-(-4z-10)



We get rid of parentheses

4z+10-27=0

We add all the numbers together, and all the variables

4z-17=0

We move all terms containing z to the left, all other terms to the right

4z=17

z=17/4

z=4+1/4

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