-2(2+3b)=10-2

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Solution for -2(2+3b)=10-2 equation: 



-2(2+3b)=10-2

We move all terms to the left:

-2(2+3b)-(10-2)=0

We add all the numbers together, and all the variables

-2(3b+2)-8=0

We multiply parentheses

-6b-4-8=0

We add all the numbers together, and all the variables

-6b-12=0

We move all terms containing b to the left, all other terms to the right

-6b=12

b=12/-6

b=-2

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