-2(2+5b)+2(1+3b)=3b-7-8b-3

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Solution for -2(2+5b)+2(1+3b)=3b-7-8b-3 equation: 



-2(2+5b)+2(1+3b)=3b-7-8b-3

We move all terms to the left:

-2(2+5b)+2(1+3b)-(3b-7-8b-3)=0

We add all the numbers together, and all the variables

-2(5b+2)+2(3b+1)-(-5b-10)=0

We multiply parentheses

-10b+6b-(-5b-10)-4+2=0

We get rid of parentheses

-10b+6b+5b+10-4+2=0

We add all the numbers together, and all the variables

b+8=0

We move all terms containing b to the left, all other terms to the right

b=-8

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