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-2(2-2b)=3(b-5)-4
We move all terms to the left:
-2(2-2b)-(3(b-5)-4)=0
We add all the numbers together, and all the variables
-2(-2b+2)-(3(b-5)-4)=0
We multiply parentheses
4b-(3(b-5)-4)-4=0
We calculate terms in parentheses: -(3(b-5)-4), so:We get rid of parentheses
3(b-5)-4
We multiply parentheses
3b-15-4
We add all the numbers together, and all the variables
3b-19
Back to the equation:
-(3b-19)
4b-3b+19-4=0
We add all the numbers together, and all the variables
b+15=0
We move all terms containing b to the left, all other terms to the right
b=-15
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