-2(2-2b)=3(b-5)-4

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Solution for -2(2-2b)=3(b-5)-4 equation: 



-2(2-2b)=3(b-5)-4

We move all terms to the left:

-2(2-2b)-(3(b-5)-4)=0

We add all the numbers together, and all the variables

-2(-2b+2)-(3(b-5)-4)=0

We multiply parentheses

4b-(3(b-5)-4)-4=0



We calculate terms in parentheses: -(3(b-5)-4), so:

3(b-5)-4

We multiply parentheses

3b-15-4

We add all the numbers together, and all the variables

3b-19

Back to the equation:

-(3b-19)



We get rid of parentheses

4b-3b+19-4=0

We add all the numbers together, and all the variables

b+15=0

We move all terms containing b to the left, all other terms to the right

b=-15

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