-2(2-3x)-(13x-10)=-12+3(x-2)

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Solution for -2(2-3x)-(13x-10)=-12+3(x-2) equation:



-2(2-3x)-(13x-10)=-12+3(x-2)
We move all terms to the left:
-2(2-3x)-(13x-10)-(-12+3(x-2))=0
We add all the numbers together, and all the variables
-2(-3x+2)-(13x-10)-(-12+3(x-2))=0
We multiply parentheses
6x-(13x-10)-(-12+3(x-2))-4=0
We get rid of parentheses
6x-13x-(-12+3(x-2))+10-4=0
We calculate terms in parentheses: -(-12+3(x-2)), so:
-12+3(x-2)
determiningTheFunctionDomain 3(x-2)-12
We multiply parentheses
3x-6-12
We add all the numbers together, and all the variables
3x-18
Back to the equation:
-(3x-18)
We add all the numbers together, and all the variables
-7x-(3x-18)+6=0
We get rid of parentheses
-7x-3x+18+6=0
We add all the numbers together, and all the variables
-10x+24=0
We move all terms containing x to the left, all other terms to the right
-10x=-24
x=-24/-10
x=2+2/5

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