-2(2-3x)-(13x-10)=-12+3(x-2)

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Solution for -2(2-3x)-(13x-10)=-12+3(x-2) equation: 



-2(2-3x)-(13x-10)=-12+3(x-2)

We move all terms to the left:

-2(2-3x)-(13x-10)-(-12+3(x-2))=0

We add all the numbers together, and all the variables

-2(-3x+2)-(13x-10)-(-12+3(x-2))=0

We multiply parentheses

6x-(13x-10)-(-12+3(x-2))-4=0

We get rid of parentheses

6x-13x-(-12+3(x-2))+10-4=0



We calculate terms in parentheses: -(-12+3(x-2)), so:

-12+3(x-2)

determiningTheFunctionDomain
3(x-2)-12

We multiply parentheses

3x-6-12

We add all the numbers together, and all the variables

3x-18

Back to the equation:

-(3x-18)



We add all the numbers together, and all the variables

-7x-(3x-18)+6=0

We get rid of parentheses

-7x-3x+18+6=0

We add all the numbers together, and all the variables

-10x+24=0

We move all terms containing x to the left, all other terms to the right

-10x=-24

x=-24/-10

x=2+2/5

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