-2(2-4k)-k=3(-2+2k)

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Solution for -2(2-4k)-k=3(-2+2k) equation: 



-2(2-4k)-k=3(-2+2k)

We move all terms to the left:

-2(2-4k)-k-(3(-2+2k))=0

We add all the numbers together, and all the variables

-2(-4k+2)-k-(3(2k-2))=0

We add all the numbers together, and all the variables

-1k-2(-4k+2)-(3(2k-2))=0

We multiply parentheses

-1k+8k-(3(2k-2))-4=0



We calculate terms in parentheses: -(3(2k-2)), so:

3(2k-2)

We multiply parentheses

6k-6

Back to the equation:

-(6k-6)



We add all the numbers together, and all the variables

7k-(6k-6)-4=0

We get rid of parentheses

7k-6k+6-4=0

We add all the numbers together, and all the variables

k+2=0

We move all terms containing k to the left, all other terms to the right

k=-2

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