-2(2-4x)+3-4x=6(x+2)-14x+5

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Solution for -2(2-4x)+3-4x=6(x+2)-14x+5 equation: 



-2(2-4x)+3-4x=6(x+2)-14x+5

We move all terms to the left:

-2(2-4x)+3-4x-(6(x+2)-14x+5)=0

We add all the numbers together, and all the variables

-2(-4x+2)-4x-(6(x+2)-14x+5)+3=0

We add all the numbers together, and all the variables

-4x-2(-4x+2)-(6(x+2)-14x+5)+3=0

We multiply parentheses

-4x+8x-(6(x+2)-14x+5)-4+3=0



We calculate terms in parentheses: -(6(x+2)-14x+5), so:

6(x+2)-14x+5

We add all the numbers together, and all the variables

-14x+6(x+2)+5

We multiply parentheses

-14x+6x+12+5

We add all the numbers together, and all the variables

-8x+17

Back to the equation:

-(-8x+17)



We add all the numbers together, and all the variables

4x-(-8x+17)-1=0

We get rid of parentheses

4x+8x-17-1=0

We add all the numbers together, and all the variables

12x-18=0

We move all terms containing x to the left, all other terms to the right

12x=18

x=18/12

x=1+1/2

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