-2(2/5f)=(-3(1/5))

Solution for -2(2/5f)=(-3(1/5)) equation:

-2(2/5f)=(-3(1/5))

We move all terms to the left:

-2(2/5f)-((-3(1/5)))=0


Domain of the equation: 5f)!=0

f!=0/1

f!=0

f∈R


We add all the numbers together, and all the variables

-2(+2/5f)-((-3(+1/5)))=0

We multiply parentheses

-4f-((-3(+1/5)))=0

We multiply all the terms by the denominator


-4f*5)))-((-3(+1=0

Wy multiply elements

-20f^2+1=0

a = -20; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-20)·1
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{5}}{2*-20}=\frac{0-4\sqrt{5}}{-40}
=-\frac{4\sqrt{5}}{-40}
=-\frac{\sqrt{5}}{-10}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{5}}{2*-20}=\frac{0+4\sqrt{5}}{-40}
=\frac{4\sqrt{5}}{-40}
=\frac{\sqrt{5}}{-10}
$