-2(20z+1)+3=-10(4z-3)-29

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Solution for -2(20z+1)+3=-10(4z-3)-29 equation: 



-2(20z+1)+3=-10(4z-3)-29

We move all terms to the left:

-2(20z+1)+3-(-10(4z-3)-29)=0

We multiply parentheses

-40z-(-10(4z-3)-29)-2+3=0



We calculate terms in parentheses: -(-10(4z-3)-29), so:

-10(4z-3)-29

We multiply parentheses

-40z+30-29

We add all the numbers together, and all the variables

-40z+1

Back to the equation:

-(-40z+1)



We add all the numbers together, and all the variables

-40z-(-40z+1)+1=0

We get rid of parentheses

-40z+40z-1+1=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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