-2(2b+2)+(5b-4)=0

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Solution for -2(2b+2)+(5b-4)=0 equation:


Simplifying
-2(2b + 2) + (5b + -4) = 0

Reorder the terms:
-2(2 + 2b) + (5b + -4) = 0
(2 * -2 + 2b * -2) + (5b + -4) = 0
(-4 + -4b) + (5b + -4) = 0

Reorder the terms:
-4 + -4b + (-4 + 5b) = 0

Remove parenthesis around (-4 + 5b)
-4 + -4b + -4 + 5b = 0

Reorder the terms:
-4 + -4 + -4b + 5b = 0

Combine like terms: -4 + -4 = -8
-8 + -4b + 5b = 0

Combine like terms: -4b + 5b = 1b
-8 + 1b = 0

Solving
-8 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 1b = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 1b = 0 + 8
1b = 0 + 8

Combine like terms: 0 + 8 = 8
1b = 8

Divide each side by '1'.
b = 8

Simplifying
b = 8

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