-2(2c-4)=8(-2c+1)+12c

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Solution for -2(2c-4)=8(-2c+1)+12c equation: 



-2(2c-4)=8(-2c+1)+12c

We move all terms to the left:

-2(2c-4)-(8(-2c+1)+12c)=0

We multiply parentheses

-4c-(8(-2c+1)+12c)+8=0



We calculate terms in parentheses: -(8(-2c+1)+12c), so:

8(-2c+1)+12c

We add all the numbers together, and all the variables

12c+8(-2c+1)

We multiply parentheses

12c-16c+8

We add all the numbers together, and all the variables

-4c+8

Back to the equation:

-(-4c+8)



We get rid of parentheses

-4c+4c-8+8=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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