-2(2f-4)+18f=16-3(7f+2)

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Solution for -2(2f-4)+18f=16-3(7f+2) equation: 



-2(2f-4)+18f=16-3(7f+2)

We move all terms to the left:

-2(2f-4)+18f-(16-3(7f+2))=0

We add all the numbers together, and all the variables

18f-2(2f-4)-(16-3(7f+2))=0

We multiply parentheses

18f-4f-(16-3(7f+2))+8=0



We calculate terms in parentheses: -(16-3(7f+2)), so:

16-3(7f+2)

determiningTheFunctionDomain
-3(7f+2)+16

We multiply parentheses

-21f-6+16

We add all the numbers together, and all the variables

-21f+10

Back to the equation:

-(-21f+10)



We add all the numbers together, and all the variables

14f-(-21f+10)+8=0

We get rid of parentheses

14f+21f-10+8=0

We add all the numbers together, and all the variables

35f-2=0

We move all terms containing f to the left, all other terms to the right

35f=2

f=2/35

f=2/35

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