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-2(2f-4)=-4(-f+2)f=
We move all terms to the left:
-2(2f-4)-(-4(-f+2)f)=0
We add all the numbers together, and all the variables
-2(2f-4)-(-4(-1f+2)f)=0
We multiply parentheses
-4f-(-4(-1f+2)f)+8=0
We calculate terms in parentheses: -(-4(-1f+2)f), so:We get rid of parentheses
-4(-1f+2)f
We multiply parentheses
4f^2-8f
Back to the equation:
-(4f^2-8f)
-4f^2-4f+8f+8=0
We add all the numbers together, and all the variables
-4f^2+4f+8=0
a = -4; b = 4; c = +8;
Δ = b2-4ac
Δ = 42-4·(-4)·8
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-12}{2*-4}=\frac{-16}{-8} =+2 $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+12}{2*-4}=\frac{8}{-8} =-1 $
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