-2(2g+1)+3(g-5)=16

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Solution for -2(2g+1)+3(g-5)=16 equation: 



-2(2g+1)+3(g-5)=16

We move all terms to the left:

-2(2g+1)+3(g-5)-(16)=0

We multiply parentheses

-4g+3g-2-15-16=0

We add all the numbers together, and all the variables

-1g-33=0

We move all terms containing g to the left, all other terms to the right

-g=33

g=33/-1

g=-33

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