-2(2m+4)=3(2+m)

Solution for -2(2m+4)=3(2+m) equation:

-2(2m+4)=3(2+m)

We move all terms to the left:

-2(2m+4)-(3(2+m))=0

We add all the numbers together, and all the variables

-2(2m+4)-(3(m+2))=0

We multiply parentheses

-4m-(3(m+2))-8=0


We calculate terms in parentheses: -(3(m+2)), so:

3(m+2)

We multiply parentheses

3m+6

Back to the equation:

-(3m+6)


We get rid of parentheses

-4m-3m-6-8=0

We add all the numbers together, and all the variables

-7m-14=0

We move all terms containing m to the left, all other terms to the right

-7m=14

m=14/-7

m=-2