-2(2n-2)=-28+4n

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Solution for -2(2n-2)=-28+4n equation: 



-2(2n-2)=-28+4n

We move all terms to the left:

-2(2n-2)-(-28+4n)=0

We add all the numbers together, and all the variables

-2(2n-2)-(4n-28)=0

We multiply parentheses

-4n-(4n-28)+4=0

We get rid of parentheses

-4n-4n+28+4=0

We add all the numbers together, and all the variables

-8n+32=0

We move all terms containing n to the left, all other terms to the right

-8n=-32

n=-32/-8

n=+4

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