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-2(2q-1)=1/5(7-5q)
We move all terms to the left:
-2(2q-1)-(1/5(7-5q))=0
Domain of the equation: 5(7-5q))!=0We add all the numbers together, and all the variables
q∈R
-2(2q-1)-(1/5(-5q+7))=0
We multiply parentheses
-4q-(1/5(-5q+7))+2=0
We multiply all the terms by the denominator
-4q*5(-5q+7))-(1+2*5(-5q+7))=0
Wy multiply elements
-20q^2(-+10q(-=0
We use the square of the difference formula
-20q^2(-10q(-=0
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