-2(2r-8)-r=4(r-1)+r

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Solution for -2(2r-8)-r=4(r-1)+r equation: 



-2(2r-8)-r=4(r-1)+r

We move all terms to the left:

-2(2r-8)-r-(4(r-1)+r)=0

We add all the numbers together, and all the variables

-1r-2(2r-8)-(4(r-1)+r)=0

We multiply parentheses

-1r-4r-(4(r-1)+r)+16=0



We calculate terms in parentheses: -(4(r-1)+r), so:

4(r-1)+r

We add all the numbers together, and all the variables

r+4(r-1)

We multiply parentheses

r+4r-4

We add all the numbers together, and all the variables

5r-4

Back to the equation:

-(5r-4)



We add all the numbers together, and all the variables

-5r-(5r-4)+16=0

We get rid of parentheses

-5r-5r+4+16=0

We add all the numbers together, and all the variables

-10r+20=0

We move all terms containing r to the left, all other terms to the right

-10r=-20

r=-20/-10

r=+2

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