-2(2s-)-2=-3(5s+1)-5

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Solution for -2(2s-)-2=-3(5s+1)-5 equation: 



-2(2s-)-2=-3(5s+1)-5

We move all terms to the left:

-2(2s-)-2-(-3(5s+1)-5)=0

We add all the numbers together, and all the variables

-2(+2s)-(-3(5s+1)-5)-2=0

We multiply parentheses

-4s-(-3(5s+1)-5)-2=0



We calculate terms in parentheses: -(-3(5s+1)-5), so:

-3(5s+1)-5

We multiply parentheses

-15s-3-5

We add all the numbers together, and all the variables

-15s-8

Back to the equation:

-(-15s-8)



We get rid of parentheses

-4s+15s+8-2=0

We add all the numbers together, and all the variables

11s+6=0

We move all terms containing s to the left, all other terms to the right

11s=-6

s=-6/11

s=-6/11

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