-2(2t+1)=5(2t-2)-10t

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Solution for -2(2t+1)=5(2t-2)-10t equation: 



-2(2t+1)=5(2t-2)-10t

We move all terms to the left:

-2(2t+1)-(5(2t-2)-10t)=0

We multiply parentheses

-4t-(5(2t-2)-10t)-2=0



We calculate terms in parentheses: -(5(2t-2)-10t), so:

5(2t-2)-10t

We add all the numbers together, and all the variables

-10t+5(2t-2)

We multiply parentheses

-10t+10t-10

We add all the numbers together, and all the variables

-10

Back to the equation:

-(-10)



We add all the numbers together, and all the variables

-4t+8=0

We move all terms containing t to the left, all other terms to the right

-4t=-8

t=-8/-4

t=+2

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