-2(2t+2)=-28

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Solution for -2(2t+2)=-28 equation:



-2(2t+2)=-28
We move all terms to the left:
-2(2t+2)-(-28)=0
We add all the numbers together, and all the variables
-2(2t+2)+28=0
We multiply parentheses
-4t-4+28=0
We add all the numbers together, and all the variables
-4t+24=0
We move all terms containing t to the left, all other terms to the right
-4t=-24
t=-24/-4
t=+6

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