-2(2t-2)+2t=3t-5

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Solution for -2(2t-2)+2t=3t-5 equation:



-2(2t-2)+2t=3t-5
We move all terms to the left:
-2(2t-2)+2t-(3t-5)=0
We add all the numbers together, and all the variables
2t-2(2t-2)-(3t-5)=0
We multiply parentheses
2t-4t-(3t-5)+4=0
We get rid of parentheses
2t-4t-3t+5+4=0
We add all the numbers together, and all the variables
-5t+9=0
We move all terms containing t to the left, all other terms to the right
-5t=-9
t=-9/-5
t=1+4/5

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