-2(2u-1)+4u=7+2(6u-1)

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Solution for -2(2u-1)+4u=7+2(6u-1) equation: 



-2(2u-1)+4u=7+2(6u-1)

We move all terms to the left:

-2(2u-1)+4u-(7+2(6u-1))=0

We add all the numbers together, and all the variables

4u-2(2u-1)-(7+2(6u-1))=0

We multiply parentheses

4u-4u-(7+2(6u-1))+2=0



We calculate terms in parentheses: -(7+2(6u-1)), so:

7+2(6u-1)

determiningTheFunctionDomain
2(6u-1)+7

We multiply parentheses

12u-2+7

We add all the numbers together, and all the variables

12u+5

Back to the equation:

-(12u+5)



We add all the numbers together, and all the variables

-(12u+5)+2=0

We get rid of parentheses

-12u-5+2=0

We add all the numbers together, and all the variables

-12u-3=0

We move all terms containing u to the left, all other terms to the right

-12u=3

u=3/-12

u=-1/4

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