-2(2u-1)+6u=7+3(2u-1)

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Solution for -2(2u-1)+6u=7+3(2u-1) equation:



-2(2u-1)+6u=7+3(2u-1)
We move all terms to the left:
-2(2u-1)+6u-(7+3(2u-1))=0
We add all the numbers together, and all the variables
6u-2(2u-1)-(7+3(2u-1))=0
We multiply parentheses
6u-4u-(7+3(2u-1))+2=0
We calculate terms in parentheses: -(7+3(2u-1)), so:
7+3(2u-1)
determiningTheFunctionDomain 3(2u-1)+7
We multiply parentheses
6u-3+7
We add all the numbers together, and all the variables
6u+4
Back to the equation:
-(6u+4)
We add all the numbers together, and all the variables
2u-(6u+4)+2=0
We get rid of parentheses
2u-6u-4+2=0
We add all the numbers together, and all the variables
-4u-2=0
We move all terms containing u to the left, all other terms to the right
-4u=2
u=2/-4
u=-1/2

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