-2(2u-4)+u=1+2(3u-4)

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Solution for -2(2u-4)+u=1+2(3u-4) equation: 



-2(2u-4)+u=1+2(3u-4)

We move all terms to the left:

-2(2u-4)+u-(1+2(3u-4))=0

We add all the numbers together, and all the variables

u-2(2u-4)-(1+2(3u-4))=0

We multiply parentheses

u-4u-(1+2(3u-4))+8=0



We calculate terms in parentheses: -(1+2(3u-4)), so:

1+2(3u-4)

determiningTheFunctionDomain
2(3u-4)+1

We multiply parentheses

6u-8+1

We add all the numbers together, and all the variables

6u-7

Back to the equation:

-(6u-7)



We add all the numbers together, and all the variables

-3u-(6u-7)+8=0

We get rid of parentheses

-3u-6u+7+8=0

We add all the numbers together, and all the variables

-9u+15=0

We move all terms containing u to the left, all other terms to the right

-9u=-15

u=-15/-9

u=1+2/3

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