-2(2u-6)+2u=4(u+7)

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Solution for -2(2u-6)+2u=4(u+7) equation: 



-2(2u-6)+2u=4(u+7)

We move all terms to the left:

-2(2u-6)+2u-(4(u+7))=0

We add all the numbers together, and all the variables

2u-2(2u-6)-(4(u+7))=0

We multiply parentheses

2u-4u-(4(u+7))+12=0



We calculate terms in parentheses: -(4(u+7)), so:

4(u+7)

We multiply parentheses

4u+28

Back to the equation:

-(4u+28)



We add all the numbers together, and all the variables

-2u-(4u+28)+12=0

We get rid of parentheses

-2u-4u-28+12=0

We add all the numbers together, and all the variables

-6u-16=0

We move all terms containing u to the left, all other terms to the right

-6u=16

u=16/-6

u=-2+2/3

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