-2(2u-6)+2u=5(5u-4)

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Solution for -2(2u-6)+2u=5(5u-4) equation: 



-2(2u-6)+2u=5(5u-4)

We move all terms to the left:

-2(2u-6)+2u-(5(5u-4))=0

We add all the numbers together, and all the variables

2u-2(2u-6)-(5(5u-4))=0

We multiply parentheses

2u-4u-(5(5u-4))+12=0



We calculate terms in parentheses: -(5(5u-4)), so:

5(5u-4)

We multiply parentheses

25u-20

Back to the equation:

-(25u-20)



We add all the numbers together, and all the variables

-2u-(25u-20)+12=0

We get rid of parentheses

-2u-25u+20+12=0

We add all the numbers together, and all the variables

-27u+32=0

We move all terms containing u to the left, all other terms to the right

-27u=-32

u=-32/-27

u=1+5/27

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