-2(2v-1)+3v=5(v+2)

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Solution for -2(2v-1)+3v=5(v+2) equation: 



-2(2v-1)+3v=5(v+2)

We move all terms to the left:

-2(2v-1)+3v-(5(v+2))=0

We add all the numbers together, and all the variables

3v-2(2v-1)-(5(v+2))=0

We multiply parentheses

3v-4v-(5(v+2))+2=0



We calculate terms in parentheses: -(5(v+2)), so:

5(v+2)

We multiply parentheses

5v+10

Back to the equation:

-(5v+10)



We add all the numbers together, and all the variables

-1v-(5v+10)+2=0

We get rid of parentheses

-1v-5v-10+2=0

We add all the numbers together, and all the variables

-6v-8=0

We move all terms containing v to the left, all other terms to the right

-6v=8

v=8/-6

v=-1+1/3

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