-2(2v-1)+4v=4(v+3)

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Solution for -2(2v-1)+4v=4(v+3) equation: 



-2(2v-1)+4v=4(v+3)

We move all terms to the left:

-2(2v-1)+4v-(4(v+3))=0

We add all the numbers together, and all the variables

4v-2(2v-1)-(4(v+3))=0

We multiply parentheses

4v-4v-(4(v+3))+2=0



We calculate terms in parentheses: -(4(v+3)), so:

4(v+3)

We multiply parentheses

4v+12

Back to the equation:

-(4v+12)



We add all the numbers together, and all the variables

-(4v+12)+2=0

We get rid of parentheses

-4v-12+2=0

We add all the numbers together, and all the variables

-4v-10=0

We move all terms containing v to the left, all other terms to the right

-4v=10

v=10/-4

v=-2+1/2

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