-2(2v-1)+6v=3+4(4v-2)

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Solution for -2(2v-1)+6v=3+4(4v-2) equation: 



-2(2v-1)+6v=3+4(4v-2)

We move all terms to the left:

-2(2v-1)+6v-(3+4(4v-2))=0

We add all the numbers together, and all the variables

6v-2(2v-1)-(3+4(4v-2))=0

We multiply parentheses

6v-4v-(3+4(4v-2))+2=0



We calculate terms in parentheses: -(3+4(4v-2)), so:

3+4(4v-2)

determiningTheFunctionDomain
4(4v-2)+3

We multiply parentheses

16v-8+3

We add all the numbers together, and all the variables

16v-5

Back to the equation:

-(16v-5)



We add all the numbers together, and all the variables

2v-(16v-5)+2=0

We get rid of parentheses

2v-16v+5+2=0

We add all the numbers together, and all the variables

-14v+7=0

We move all terms containing v to the left, all other terms to the right

-14v=-7

v=-7/-14

v=1/2

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