-2(2v-1)+6v=6(v+2)

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Solution for -2(2v-1)+6v=6(v+2) equation: 



-2(2v-1)+6v=6(v+2)

We move all terms to the left:

-2(2v-1)+6v-(6(v+2))=0

We add all the numbers together, and all the variables

6v-2(2v-1)-(6(v+2))=0

We multiply parentheses

6v-4v-(6(v+2))+2=0



We calculate terms in parentheses: -(6(v+2)), so:

6(v+2)

We multiply parentheses

6v+12

Back to the equation:

-(6v+12)



We add all the numbers together, and all the variables

2v-(6v+12)+2=0

We get rid of parentheses

2v-6v-12+2=0

We add all the numbers together, and all the variables

-4v-10=0

We move all terms containing v to the left, all other terms to the right

-4v=10

v=10/-4

v=-2+1/2

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