-2(2v-2)+8v=2+4(3v-1)

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Solution for -2(2v-2)+8v=2+4(3v-1) equation: 



-2(2v-2)+8v=2+4(3v-1)

We move all terms to the left:

-2(2v-2)+8v-(2+4(3v-1))=0

We add all the numbers together, and all the variables

8v-2(2v-2)-(2+4(3v-1))=0

We multiply parentheses

8v-4v-(2+4(3v-1))+4=0



We calculate terms in parentheses: -(2+4(3v-1)), so:

2+4(3v-1)

determiningTheFunctionDomain
4(3v-1)+2

We multiply parentheses

12v-4+2

We add all the numbers together, and all the variables

12v-2

Back to the equation:

-(12v-2)



We add all the numbers together, and all the variables

4v-(12v-2)+4=0

We get rid of parentheses

4v-12v+2+4=0

We add all the numbers together, and all the variables

-8v+6=0

We move all terms containing v to the left, all other terms to the right

-8v=-6

v=-6/-8

v=3/4

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