-2(2x+1)-2x-4=3(2-x)1

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Solution for -2(2x+1)-2x-4=3(2-x)1 equation: 



-2(2x+1)-2x-4=3(2-x)1

We move all terms to the left:

-2(2x+1)-2x-4-(3(2-x)1)=0

We add all the numbers together, and all the variables

-2(2x+1)-2x-(3(-1x+2)1)-4=0

We add all the numbers together, and all the variables

-2x-2(2x+1)-(3(-1x+2)1)-4=0

We multiply parentheses

-2x-4x-(3(-1x+2)1)-2-4=0



We calculate terms in parentheses: -(3(-1x+2)1), so:

3(-1x+2)1

We multiply parentheses

-3x+6

Back to the equation:

-(-3x+6)



We add all the numbers together, and all the variables

-6x-(-3x+6)-6=0

We get rid of parentheses

-6x+3x-6-6=0

We add all the numbers together, and all the variables

-3x-12=0

We move all terms containing x to the left, all other terms to the right

-3x=12

x=12/-3

x=-4

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