-2(2x+3)+1=5(x-1/5)

Solution for -2(2x+3)+1=5(x-1/5) equation:

-2(2x+3)+1=5(x-1/5)

We move all terms to the left:

-2(2x+3)+1-(5(x-1/5))=0

We add all the numbers together, and all the variables

-2(2x+3)-(5(+x-1/5))+1=0

We multiply parentheses

-4x-(5(+x-1/5))-6+1=0

We multiply all the terms by the denominator


-4x*5))-(5(+x-1-6*5))+1*5))=0

We add all the numbers together, and all the variables

-4x*5))-(5(x-31))+1*5))=0

We add all the numbers together, and all the variables

-4x*5))-(5(x=0

Wy multiply elements

-20x^2=0

a = -20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-20)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-40}=0$