-2(2x+3)+4(3x-5)=-42

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Solution for -2(2x+3)+4(3x-5)=-42 equation: 



-2(2x+3)+4(3x-5)=-42

We move all terms to the left:

-2(2x+3)+4(3x-5)-(-42)=0

We add all the numbers together, and all the variables

-2(2x+3)+4(3x-5)+42=0

We multiply parentheses

-4x+12x-6-20+42=0

We add all the numbers together, and all the variables

8x+16=0

We move all terms containing x to the left, all other terms to the right

8x=-16

x=-16/8

x=-2

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